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A capacitor of unknown capacitance is connected across a battery of V volts . The charge stored in it is 360 mu C . When potential across the capacitor is reduced by 120 V , the charge stored in it becomes 120 mu C. Calculate : The potential V and the unknown capacitance C . |
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Answer» Solution :LET the CAPACITANCE of given capacitor be C mF . Then as PER data given in the question : CV = `360 mu C "" …. (1)` and`C ( V - 120) = 120 mu C "" …. (2)` Substracting (2) from (1) , we have `C xx 120 = 240 mu C implies C = (240 mu C)/(120 V) = 2 mu F` and from (1) `V = (360 mu C)/(C) = (360 mu C)/(2 mu F) = 180 V ` |
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