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A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will beA. `(C_(2))/(C_(1)+C_(2))V_(0)`B. `(C_(1))/(C_(1)+C_(2))V_(0)`C. `(C_(1)+C_(2))/(C_(2))`D. `(C_(1)+C_(2))/(C_(1))V_(0)` |
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Answer» Correct Answer - B |
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