1.

A car accelerates from rest at a constant rate a for some time after which it retards at a constant rate to come to rest. If the time elapsed is t, maximum velocity reached is

Answer»

`V=t((ALPHA beta)/(alpha+beta))`
`v=t((alpha beta)/(alpha-beta))`
`v=t((alpha^2)/(alpha-beta))`
`v=t((beta^2)/(alpha-beta))`

Solution :TIME during ACCELERATION + time during retardation=t
`(V-0)/(alpha)+(0-V)/(-beta)=t implies(V)/(alpha)+(V)/(beta)=t`
`V((1)/(alpha)+(1)/(beta))=t implies V=((alpha)/(alpha+beta))t`


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