:-The Distance Covered by the car in 15 s.Given :-Initial velocity = 60 m/minTime of Retardation = 15 secWe KNOW :-First EQUATION of Motion :-Where :-v = Final Velocityu = Initial velocitya = Acceleration due to gravityt = TIME TakenSecond Equation of Motion :-Where :-u = Initial velocityS = Distance Traveleda = Acceleration due to gravityt = Time TakenConcept :-The Final velocity of the car will be zero.i.e, (v = 0)Acceleration will be negative (or Retarded) as the brakes were applied .Convert the initial velocity in m/s from m/min.Given ,Initial velocity = 60 m/min.To convert it in m/s ,. divide the initial velocity by 1/60.==> 60 m/min==> 60 m/min = (60 × 1/60) m/s==> 60 m/min = 1 m/sHence, the initial velocity of the car is 1 m/s.Solution :-To Find the Acceleration of the car :-u = 1 m/sv = 0 m/st = 15 sLet the Acceleration produced be a m/s².Now, Using the First Equation of Motion and SUBSTITUTING the values in it , we get :-Hence, the Acceleration is -0.07 m/s² or Retardation is 0.07 m/s².To Find the Distance covered by the car :-u = 1 m/sa = - 0.07 m/s²t = 15 sLet the distance covered be S m.Using the SECOND Equation of Motion and substituting the values in it , we get :Hence, the distance covered by the car is 7.1 m.