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A car is moving with constant speed on a road as shown in figure. The normal reaction by the road on the car is `N_(A),N_(B), N_(C)` when it is at the points A,B and C respectively. A. `N_(A)=N_(B)`B. `N_(A)gtN_(B)`C. `N_(A)ltN_(B)`D. `N_(C)=N_(A)` |
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Answer» Correct Answer - B for normal reaction at points A and B `mg-N=(mv^(2))/r` `N=mg=(mv^(2))/r` `rArr N_(A) gt N_(B)` and normal reaction at C is `N_(O)`=mg , so `N_(C) gt N_(A) gt N_(B)` |
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