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A car is travelling along a circular curve that has a radius of `50m` . If its speed is `16m//s` and is increasing uniformly at `8m//s^(2)` . Determine the magnitude of its acceleration at this instant. |
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Answer» Given, tangential acceleration `a_(t)=8ms^(-2)` Radius R = 50 m, Speed v = 16`ms^(-1)` `therefore"Radial acceleration" a_(r)=(v^(2))/(R)=((16)^(2))/(50)=(256)/(50)` Magnitude of net acceleration of the car. `a=sqrt(a_(t)^(2)+a_(r)^(2))=sqrt((8)^(2)+((256)/(50))^(2))=9.5ms^(-2)` |
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