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A car is travelling at 36 kmph on a road . The maximum turning radius of the car is 20 m ans `g=10m//s^(2)` .Then the coefficient of friction between its tyres and the road isA. `0.2`B. `0.4`C. `0.5`D. `0.8` |
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Answer» Correct Answer - C `v=36xx(5)/(18)=10m//s, r=20m, g=10 m//s^(2), mu=?` `v=sqrt(mu rg)` `v^(2)=mu rg therefore mu=(v^(2))/(rg)` `=(10xx10)/(20xx10)=0.5.` |
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