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A car leaves point P at 1310 ( 1.10 p.m. ) hours, passing through point Q at 1358 (1.58 p.m. ) hours and finally reaches point R at 1540 (3.40 p.m.) hours. The average speed of the car from Q to R is 2 times the average speed from P to Q.P to Q = 40 kmFORMULA:average speed = total distance / total time Calculate the average speed, in km/h of the whole journey of the car. |
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Answer» Answer: A car leaves point P at 1310 ( 1.10 p.m. ) hours, passing through point Q at 1358 (1.58 p.m. ) hours and FINALLY reaches point R at 1540 (3.40 p.m.) hours. The average speed of the car from Q to R is 2 TIMES the average speed from P to Q. P to Q = 40 km FORMULA: average speed = total distance / total TIME Calculate the average speed, in km/h of the whole JOURNEY of the car. |
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