1.

A car moving at a speed V is stopped by a retarding force F in a distance S. If the retarding force were 6F, the car will be stopped in a distance :

Answer»

`(S)/(12)`
`a=(1)/(3)G`
`(S)/(6)`
`(S)/(3)`

Solution :Work done = change is K.E.
`F.S. =(1)/(2) m upsilon^(2)`
`S=(m upsilon^(2))/(2F)`For constant m and `upsilon`
`Sprop(1)/(F)`
When FORCE BECOMES 6 times then distance `(1)/(6)th`
Hence correct CHOICE is (c).


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