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A car moving with a speed of 50 km/hra speed of 100 km/hr the minimum stopping distance iscan be stopped by brakes after at least 6m. If the same car is moving at |
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Answer» Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s Final velocity, v = 0 Distance travelled before coming to rest, s = 6 m Using, v2= u2+ 2as => a = -u2/(2s) => a = -16.075 m/s2 Again, u = 100 km/h = 500/18 m/s v = 0 a = -16.075 m/s2 Now, v2= u2+ 2as => s = -u2/(2a) = 24 m thank you is this the in your syllabus |
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