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A car moving with speed of 50 m/s ,can be stopped by brakes after at least 6m. if the same car is moving at a speed of 100m/s, the minimum stopping distance is |
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Answer»
ANSWER If FINAL velocity is zero and ACCELERATION is −ve then. s= 2a/u ^2 s∝u ^2 So, if the velocity is doubled than stopping distance will become 2 2 =4 =6×4 =24 m. |
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