1.

A car moving with speed of 50 m/s ,can be stopped by brakes after at least 6m. if the same car is moving at a speed of 100m/s, the minimum stopping distance is

Answer»

ANSWER

If FINAL velocity is zero and ACCELERATION is −ve then.

s= 2a/u ^2

s∝u ^2

So, if the velocity is doubled than stopping distance will become 2

2

=4 =6×4

=24 m.



Discussion

No Comment Found