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A car of mass 1000kg accelerates uniformly from rest to a velocity of `54km//h` in 5 seconds. Calculate (i) its acceleration (ii) its gain in KE (iii) average power of the engine during this period. |
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Answer» Here, `m=1000kg, u=0` `u=54km//h=15m//s` `t=5s, a=?, KE=?, Power =?` From `v=u+at, a=(v-u)/(t)=(15-0)/(5)=3m//s^(2)` Gain in KE `=(1)/(2)mv^(2)-0=(1)/(2)xx1000(15)^(2)` `=1.125xx10^(5)J` Power `= ("work")/("time")=(KE)/(t)=(1.125xx10^(5))/(5)` `=22500watt` |
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