1.

A car of mass 100kg is moving with a certain velocity. It is brought to rest by the application of brakes, within a distance of 10m when the average resistance being offered to it is 250N.What was the velocity of the motor car?

Answer»

5√2 m/sExplanation:m= 100 KGS= 10 mf=-250Ninitial VELOCITY=? FINAL velocity=0acceleration= F/M=-250/100=-2.5m/s2we have v2-u2= 2asu2= v2-2as= 0-2(-2.5)×10 m2/s2=50 m2/s2u=√50u=√25×2u=5√2m/s



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