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InterviewSolution
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A car of mass `500kg` moving with a speed `36kmh` in a straight road unidirectionally doubles its speed in `1min`. Find the power delivered by the engine. |
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Answer» Its initial speed `v_1=(36000)/(3600)=10ms^-1` If the car doublese its speed, finally its speed becomes `v_2=20ms^-1`. Change in KE of the car `=DeltaKE=(1//2)mv_2^2-(1//2)mv_1^2` During `Deltat=1min=60s` the power delivered by the engine, P=Work done/Time Taken=`(|DeltaKE|)/(Deltat)` `=(1/2xxm[v_2^2-v_1^2])/(Deltat)` `=(1//2xx500[20^2-10^2])/(60)=1250W` |
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