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A car of mass m moves in a horizontal circular path of radius r meter. At an instant its speed is `Vm//s` and is increasing at a rate of a `m//sec^(2)`. Then the acceleration of the car is:A. `(a^(2)+(v^(2))/(r))`B. `sqrt(a^(2)+((v^(2))/(r)))`C. `a^(2)+((v^(2))/(r))^(2)`D. `sqrt((a^(2))+((v^(2))/(r))^(2))` |
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Answer» Correct Answer - D `a=sqrt(a^(2)+((v^(2))/(r)))^(2)` |
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