A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(m upsilon)/(2)` eastward and is exerted by the car engineB. `(m upsilon)/(2)` eastward and is due to the friction on the tyres exerted by the roadC. more than `(m upsilon)/(2)` eastward exerted due to the engine and overcomes the friction of the roadD. `m (upsilon)/(2)` exerted by the engine

A car of mass m starts from rest and acquires a velocity along east `u

1.	A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(m upsilon)/(2)` eastward and is exerted by the car engineB. `(m upsilon)/(2)` eastward and is due to the friction on the tyres exerted by the roadC. more than `(m upsilon)/(2)` eastward exerted due to the engine and overcomes the friction of the roadD. `m (upsilon)/(2)` exerted by the engine
Answer» Correct Answer - b Here, mass of car `=m` As it starts from rest, `u = 0` final velocity along east `upsilon = upsilonhati , t =2 sec` From `upsilon = u + at` `upsilonhati = 0 + vec (a) xx 2, vec(a) = (upsilon)/(2) hati` `vec(F) = m vec(a) =( m upsilon)/(2) hati` ,force of car is` (m upsilon)/(2)` east ward This is due to friction on the tyres exerted by the road .

Discussion

No Comment Found

Related InterviewSolutions

A horizontal force of `1.2kg` is applied on a `1.5kg` block, which rests on a horizontal surface If the coefficient of friction is `0.3` find the acceleration produced in the block.
A block of mass m slides down on a wedge of mass M as shown in figure .Let `a_(1)` be the asseleration of the acceleration of and `a_(2)` the the acceleration od block 1`N_(1)` is the normal reaction between block and wedge and `N_(2)` the normal reaction between wedge and gound .frication is absent everwhere .Select the correct alternative(s) A. `N_(2)lt(M+m)g`B. `N_(2)ltM(g cos theta-|a_(1)|sintheta)`C. `N_(1)sin theta=M|a_(1)|`D. `ma_(2)=-Ma_(1)`
A hammer weighing 3 kg moving with a velocity of `10ms^(-1)` strikes against the head fo a spike and drives it into a block of wood. If the hammer comes to rest in `0.025` s, find (i) the impulse and (ii) the average force on the head of the spike.
A man of mass 70 kg stands on a weighing machine in a lift, which is moving (a) upwards with a uniform speed of `10ms^(-1)` (b) downwards with a uniform acceleration of `5 ms^(-2)` (c) upwards with a uniform acceleration of `5 ms^(-2)` What would be the readings on the scale in each case ? (d) What would be the reading if the lift mechanism failed and it hurtled down freely under gravity ?
A body wights 8 g when placed on one pan and 18 g when placed on the other pan of a false balance .If the beam is horizontal when both the pans are empty the weght of the body is 4 xg Find value of x.
A racing car travels on a track (without banking) ABCDEFA ABC is a circular are of radius ` 2 R.CD` and `FA` are strainght paths of length `R` and `DEF` is a circular are of radius `R=100m` The co- efficient of friction on the road is `mu = 0.1` The maximum speed of ther car is `50ms^(-1)` Find the minimum time for completing one round .
A constant force acting on a body of mass of 5 kg change its speed from `5ms^(-1) "to" 10ms^(-1)` in 10 s without changing the direction of motion. The force acting on the body isA. 1.5NB. 2NC. 2.5ND. 5N
Given the magnitude and direction of the force acting on a stone of mass 0.1 kg (a) just after it is dropped from the window of a stationary train (b) just after it is dropped from the window of a train running at a constant velocity of `36 km//hr` (c) just after it is droped from the window of a train accelerating with `1 ms^(-2)` (d) lying on the floor of a trin which is accelerating with `1 ms^(-2)` the stone being at rest relative to the train . Neglect the resistance of air throuhout .
When forces `F_1`, `F_2`, `F_3`, are acting on a particle of mass m such that `F_2` and `F_3` are mutually perpendicular, then the particle remains stationary. If the force `F_1` is now removed then the acceleration of the particle isA. (a) `F//m`B. (b) `F_2F_3//mF_1`C. (c) `(F_2-F_3)//m`D. (d) `F_2//m`
If a body looses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest?A. (a) 1 cmB. (b) 2 cmC. (c) 3 cmD. (d) 4 cm

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment