A horizontal force of `1.2kg` is applied on a `1.5kg` block, which rests on a horizontal surface If the coefficient of friction is `0.3` find the acceleration produced in the block.

A horizontal force of `1.2kg` is applied on a `1.5kg` block, which res

1.	A horizontal force of `1.2kg` is applied on a `1.5kg` block, which rests on a horizontal surface If the coefficient of friction is `0.3` find the acceleration produced in the block.
Answer» Correct Answer - `4.9ms^(-2)` Here, `P = 1.2kg = 1.2 xx 9.8 N` `m = 1.5kg, mu = 0.3, a =`? Force of friction `F = muR = mu mg` `=0.3 xx 1.5 xx 9.8 N = 0.45 xx 9.8 N` `:.` force that produces acceleration `f = P - F = 1.2 xx 9.8 - 0.45 xx 9.8` `= 9.8 (1.2 - 0.45) = 9.8 xx 0.75 N` `a = (f)/(m) = (9.8 xx 0.75)/(1.5) = 4.9 ms^(-2)` .

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A horizontal force of `1.2kg` is applied on a `1.5kg` block, which rests on a horizontal surface If the coefficient of friction is `0.3` find the acceleration produced in the block.

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