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A constant force acting on a body of mass of 5 kg change its speed from `5ms^(-1) "to" 10ms^(-1)` in 10 s without changing the direction of motion. The force acting on the body isA. 1.5NB. 2NC. 2.5ND. 5N |
Answer» Correct Answer - C Here, 5kg, u=`5ms^(-1), v=10ms^(-1), t=10s` using v=u+at `a=(v-u)/(t)=((10-5)ms^(-1))/(10s)=0.5ms^(-2)` As, F=ma `therefore F=(5kg)(0.5ms^(-2))=2.5N` |
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