1.

A Car Starts From Rest And Accelerates Uniform Upto Speed 90 Km/hrs In 5 Sec. Total Distance Covered By Car In This Time Will Be?

Answer»

SPEED of car at last instant of given interval 

= 90*5/ 18 m/s = 25 m/s

so average speed = 0+25 / 2

THEREFORE distance = 5 * 25/2 = 125/2 = 62.5 m.

Speed of car at last instant of given interval 

= 90*5/ 18 m/s = 25 m/s

so average speed = 0+25 / 2

Therefore distance = 5 * 25/2 = 125/2 = 62.5 m.



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