1.

a car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110m. Determine the acceleration of the car

Answer»

The car starts from rest,
initial velocity, u= 0m/sec
it ACCELERATES UNIFORMLY over a time period, t= 5.21sec
it covers a distance, s= 110m
let the acceleration be 'a'm/sec^2
we know the kinematical EQUATION,
s= UT+(1/2)at^2
so USING this equation,
110= 0*5.21 + 1/2*a*5.21*5.21
or, 110= 13.57205a
or, a= 8.1
The acceleration of the car is 8.1m/sec^2


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