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A car weighing `1000 kg` is going up an incline with a slope of `2` in `25` at a steady speed of `18 kmph`. If `g = 10 ms^(-2)`, the power of its engine isA. 4 kWB. 50 kWC. 625 kWD. 25 kW |
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Answer» Correct Answer - A `P = vecF.vec v = Fv = mg sin theta v`. |
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