1.

A car weighing 12000 kg along with the weight of its driver and is moving at a uniform speed on a road which offers same force of friction consumes one litre of petrol for every 15 km run. If combustion of petrol ganerates 3 x 10') per litre and efficiency of the engine is 50%, calculate the force of friction acting on the car during 15 km drive.

Answer»

`10^(3)` N
`0.5 xx10^(3)` N
`10^(4)` N/m
`0.5 xx10^(4)` N

Solution :Here with 50% efficiencylitre generates `1.5xx10^7 J`
which is used for driving 15 km.Thus
`F.x=1.5xx10^7 J`
or`F=(1,5xx10^7)/(15000)=10^3 N`


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