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A carbon resistor of(47 pm 4.7) k Omega is to be marked with rings of different colours for its marked with rings of different colours for its identification. The colour code sequence will be |
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Answer» GREEN - Orange - Violet - Gold R = `(47 pm 4.7) xx 10^(3) Omega` = `(47 xx 10^(3) pm 4700) Omega and (4700 xx 100)/(47000)= 10%` `= (47 xx 10^(3) pm 10% ) Omega` From colour code, `4 RARR` yellow, 7 `rarr` violet , 3 `rarr` orange, 10 % for gold. |
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