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A card is drawn at random from a pack of 52 cards. The probability that the drawn card is not an ace isA. \(\frac{1}{13}\)B. \(\frac{9}{13}\)C. \(\frac{4}{13}\)D.\(\frac{12}{13}\) |
Answer» Total numbers of elementary events are: 52 Let E be the event of drawing card other than ace Favorable numbers of events are: 52 – 4 = 48 P (not drawing ace) = P (E) = \(\frac{48}{52}\) = \(\frac{24}{26}\) = \(\frac{12}{13}\) |
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