

InterviewSolution
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A card is drawn at random from a pack of 52 cards. Find the probability that the card drawn is:(i) a spade(ii) a black card (iii) the seven of clubs (iv) jack (v) the ace of spades |
Answer» (i) a spade Total numbers of cards are 52 Total number of spade cards = 13 Probability of getting spade is = \(\frac{Total\,number\,of\,spade\,cards}{Total\,number\,of\,cards}\) = \(\frac{13}{52}\) = \(\frac{1}{4}\) (ii) a black card Total numbers of cards are 52 Cards of spades and clubs are black cards. Number of spades = 13 Number of clubs = 13 Therefore, total number of black card out of 52 cards = 13 + 13 = 26 Probability of getting black cards is = \(\frac{Total\,number\,of\,black\,cards}{Total\,number\,of\,cards}\) = \(\frac{26}{52}=\frac{1}{2}\) (iii) the seven of clubs Total numbers of cards are 52 Number of the seven of clubs cards = 1 Probability of getting the seven of clubs cards is = \(\frac{Total\,number\,of\,the\,seven\,of\,clubs\,cards}{Total\,number\,of\,cards}\) = \(\frac{1}{52}\) (iv) jack Total numbers of cards are 52 Number of jack cards = 4 Probability of getting jack cards is = \(\frac{Total\,number\,of\,jack\,cards}{Total\,number\,of\,cards}\) = \(\frac{4}{52}=\frac{1}{13}\) (v) the ace of spades Total numbers of cards are 52 Number of the ace of spades cards = 1 Probability of getting ace of spades cards is = \(\frac{Total\,number\,of\,ace\,of\,spade\,cards}{Total\,number\,of\,cards}\) = \(\frac{1}{52}=\frac{1}{52}\) |
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