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A Carnot engine, having an efficiency of `eta=1//10` as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is |
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Answer» Coefficient of performance of refrigerator `beta=(1-eta)/(eta)=(1-1//10)/(1//10)=9=("Heat extracted")/("workdone")` `therefore` Heat extracted `=9xx10=90J` |
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