InterviewSolution
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InterviewSolution
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A carnot engine operates between temperature `600 K` and `300 K`. It absorbs `100 J` from the source. Calculate the heat transferred to the sink. |
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Answer» Using: `eta_("Carnot") =1 - (T_(1))/(T_(2)) =1- (300)/(600) = (1)/(2) = 50%` Also, `eta_("carnot") = ("Work done")/("Heat abosorbed") = ("Work done")/(100)` `rArr` Work done `=100 xx (1)/(2) = 50 J` and the heat lost to the surrounding `=100 - 50 = 50 J` |
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