1.

A Carnot engine operating between temperatures T_(1) and T_(2) has efficiency (1)/(6). When T_(2) is lowered by 62 K its efficiency increase to (1)/(3). Then T_(1) and T_(2) are, resectively :

Answer»

372 K and 330 K
330 K and 268 K
310 K and 248 K
372 K and 310 K

Solution :Efficiency of engine `eta =1-(T_(2))/(T_(1))`
`rArr (T_(2))/(T_(1))=(5)/(6)"….(i)"`
`eta_(2)=1-(T_(2)-62)/(T_(1)=(1)/(3)"….(ii)"`
Solving we GET, `T_(1)=372 K and T_(2)=(5)/(6)xx372=310 K`
Correct choice : (d).


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