InterviewSolution
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InterviewSolution
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A carnot engine operating between temperatures `T_(1)` and `T_(2)` has efficiency. When `T_(2)` is lowered by 62K, its efficience increases to `(1)/(3)`. Then `T_(1)` and `T_(2)` are respectively: |
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Answer» `eta=1-(T_(2))/(T_(1))rArr(1)/(6)=1-(T_(2))/(T_(1))rArr(T_(2))/(T_(1))=(5)/(6)`.......(1) `eta_(2)=1-(T_(2)-62)/(T_(1))rArr(1)/(3)=1-(T_(2)-62)/(T_(1))` ....(2) On solving Equation (1) and (2) `T_(1)=372K` and `T_(2)=310K` |
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