InterviewSolution
Saved Bookmarks
| 1. |
A carnot engine takes 900 Kcal of heat from a reservoir at `723^(@)C ` and exhausts it to a sink at `30^(2)C` the work done by the engine isA. `2.73xx10^(6) cal`B. `3.73xx10^(6) cal`C. `6.27xx10^(5) cal`D. `3.73xx10^(5) cal` |
|
Answer» Correct Answer - C Here `Q_(1)=900 kcal =900xx10^(3) cal =9xx10^(5) cal` `T_(1)=723^(@)C=723 + 273 =996 K` `t_(2)=30^(@)C = 30 + 273 =303K` `therefore (_(1))/(Q_(2))=(T_(1))/(T_(2))` `therefore Q_(2)=(T_(2))/(T_(1))Q_(1)=(303)/(996)xx9xxx10^(5)=2.73xx10^(5) cal` Now work done by the engine W=`Q_(1)-Q_(2)` `=9x10^(5)-2.73xx10^(5)` `(9-2.73)xx10^(5)=6.27xx10^(5) cal` |
|