A cell can be balanced against `110 cm` and `100 cm` of potentiometer wire, respectively with and without being short circuited through a resistance of `10 Omega`. Its internal resistance isA. 2.0 ohmB. zeroC. 1.0 ohmD. 0.5 ohm

A cell can be balanced against `110 cm` and `100 cm` of potentiometer

1.	A cell can be balanced against `110 cm` and `100 cm` of potentiometer wire, respectively with and without being short circuited through a resistance of `10 Omega`. Its internal resistance isA. 2.0 ohmB. zeroC. 1.0 ohmD. 0.5 ohm
Answer» Correct Answer - C `E prop I_(1) and E-(E)/(R+r),r prop l_(2)` `rArr (r+R)/(R)=(l_(1))/(l_(2))` `rArr r=((l_(1))/(l_(2))-1).R` `=(110-100)/(100)xx10=1Omega`

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A cell can be balanced against `110 cm` and `100 cm` of potentiometer wire, respectively with and without being short circuited through a resistance of `10 Omega`. Its internal resistance isA. 2.0 ohmB. zeroC. 1.0 ohmD. 0.5 ohm

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