1.

A cell is constructed using Pb^(2+), Pb and Ni^(2+), Ni electrodes. If E^@ values of Pb and Ni electrode are respectively -0.13 and -0.25 V, write (a) the cell reaction and (b) cell notation.

Answer»

Solution :Reduction POTENTIAL of Ni electrode is less and hence it reduces `PB^(2+)` ions.
The CELL REACTIONS is written as, `Ni + Pb^(2+) to Pb + Ni^(2+)`
The oxidation half reaction is , `Ni to Ni^(2+) + 2e^(-)`
The reduction half reaction is , `Pb^(2+) + 2e^(-) to Pb`.
The cell is written as, `Ni , Ni^(2+) (aq)//Pb^(2+)(aq),Pb.`


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