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A cell is e.m.f 2V and internal resistance 1 Omega is connected to a potentiometer of length 1m and resistance 4 Omega Calculate the potential drop per cm. |
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Answer» Solution :e.m.f of cell E = 2V Internal RESISTANCE of potentiometer wire R=` 4 Omega` Potential drop `V= E((R)/(R+r))= (2xx4)/(4+1) = 1.6 V` Potential drop PER cm `=V/l = (1.6)/(100) = 1.6 xx 10^(-2) ` volt/cm. |
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