1.

A cell is represented by Zn| Zn_((aq))^(+ +) ||Cu_((aq))^(+ +) | CugivenCu^(+ +)+2 e^(-) toCu , E^(@)= + 0.35Vand Zn^(+ +) +2e^(- )to Zn ,E^@=- 0.763V Calculate emf of the cell and state whether the cell reaction will be spontaneous or non-spontaneous ?

Answer»

1.113, spontaneous
`-0.567`, non-spontaneous
`-1.113`, non-spontaneous
5.678 spontaneous

Solution :Halfcellreactionof aodei.e,L.H.Selectrons
` Zn-2e^(-) hArrZn^( + +)`
halfcellreactionof cathodei.e.,R.H.Selectrode
` Cu^( + +) hArrZn^( ++)+cu`
`E_("cell")^@=E_("RED ")^(@)` ofR.H.S-` E_("Red ")^@ `ofL.H.S
`= + 0.35- ( - 0.763)= 1.113` VOLT
since `E_("cell")^@ `is POSITIVEAND hence`DELTAG `is negativeandthereforeteh cellreactionis spontaneous


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