1.

A cell of e.m.f 2 volt and internal resistance 1.5Omega is connected to the ends of 1m long wire. The resistance of wire is 0.5Omega//m. Find the value of potential gradient on the wire.

Answer»

Solution :`X=(IR)/(L )=((E)/(R+r))(R )/(L)=(2xx0.5)/(0.5+1.5)=0.5V//m`


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