A cell of emf 12v is connected in series with a 5ohms resistor. Determ

1.	A cell of emf 12v is connected in series with a 5ohms resistor. Determine the current in the circuit.
Answer» V=IR ⇒I=V/R ⇒I=12/5=2.4 Therefore the correct answer is 2.4A V = 12 v R = 5 Ω V = iR \(i = \frac VR\) \(i = \frac {12}5\) i = 2.4 A

A cell of emf 12v is connected in series with a 5ohms resistor. Determine the current in the circuit.

Answer» V=IR

⇒I=V/R

⇒I=12/5=2.4

Therefore the correct answer is 2.4A

V = 12 v

R = 5 Ω

V = iR

\(i = \frac VR\)

\(i = \frac {12}5\)

i = 2.4 A