1.

A cell of emf 2.0 V and internal resistance 0.1 Omega is connected with a resistance of 3.9Omega. The voltage across the cell terminals will be

Answer»

0.50 V
1.90 V
1.95 V
2.0 V

Solution :`V = (EPSI R)/((R + r))= (2.0 XX 3.9)/((3.9 + 0.1)) = 1.95 V`


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