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A cellon open circuit has e.m.f 2.0 V and in closed circuit having current of 0.05 A , the p.d is 1.5 V . Calculate internal resistance of the cell. |
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Answer» Solution :e.m.f of CELL E= 2V Current in CIRCUIT I = 0.05 A p.d ACROSS resistance V= 1.5 V Let .R. be the internal resistance of the cell E= (Ir+V) `r= (E-V)/(I)` `=(2-1.5)/(0.05) = (0.5)/(0.05) =10 Omega` Internal resistance of the cell is `10 Omega` |
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