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A certain buffer solutions contains equal concentration of X^(-) and HX. The K_(b) for HX is 10^(-10). The pH of the buffer is |
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Answer» 4 `K_(b) = ([OH^(-)][HX])/([X^(-)])` `HX hArr H^(+) + X^(-)` `K_(a) = ([H^(+)][X^(-)])/([HX]), :. K_(a) xx K_(b) = [H^(+)][OH^(-)] = K_(w) = 10^(-14)` HENCE `K_(a) = 10^(-4)` Now as `[X^(-)] = [HX], pH = pK_(a) = 4`. |
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