1.

A certain calorimeter has a water equivalent of 4.9 gm. That is in heat exchanges, the calorimeter behaves like 4.9 gm of water. It contains 40 gm of oil at 50.0^(@)C. When 100 gm of lead at 30.0^(@)C is added, the final temperature is 48.0^(@)C. What is the specific heat capacity of the oil? [Take S_("water")=1cal//gm.^(@)C, S_("lead")=0.305"cal"//gm.^(@)C]

Answer»


ANSWER :`0.563 "CAL"/GM.^(@)C`


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