1.

A certain charge 2Q is divided at first into two parts q_(1) and q_(2). Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then Q/(q_(1)) = ________.

Answer»

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4
`0.5`
2

Solution :`q_1+q_2= 2Q`
`F alphaq_1 q_2`
` alpha q_1(2 Q -q_1)`
` F alpha2q_1 Q-q_(1)^2`
`(dF)/(dq_1) =0implies 2Q-2q_1=0 thereforeq_1=Q`
`(q_1)/(Q)=1`


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