1.

A certain first order reaction is half completed in 46 min. Calculate the rate constant and also time for 75% completion of the reaction.

Answer»

SOLUTION :DATA : `t_(1//2) = 46` min, ` k = ? `
(i) To Find value of k
`k = (0.693)/(t_(1//2)) = (0.693)/(46) = 0.015 min^(-1)`
(ii) To find t at 75% completion of reaction.
` k = (2.303)/(t_(75%)) XX log""([R]_(0))/([R])`
`t_(75%) = (2.303)/(0.015) xxlog""(100)/(35)`
`t_(75%) = 92.42`min


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