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A certain gas takes three times as long to effuse out as helium. Its molar mass will beA. 36 uB. 64 uC. 9 uD. 27 u |
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Answer» Correct Answer - A `(r_(1))/(r_(2))=sqrt((M_(w_(2)))/(M_(w_(1))))` `(V_(1))/(t_(1))xx(t_(2))/(V_(2))=sqrt((M_(w_(2)))/(M_(w_(a))))` volume is same `(3)/(1)=sqrt((M_(w_(2)))/(4))` `9=(M_(w_(2)))/(4)" "therefore M_(w_(2))=36` |
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