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A certain oxide of iodine has been found to contain iodine and oxygen. The ratio iodine : oxygen is 254: 112. On being dissolved in water this oxide can produce

Answer»

`HIO_(2)`
`HIO_(3)`
`HIO_(4)`
`H_(5)IO_(6)`

Solution :Mole ratio of iodine : oxygen
`= 254/127 : 112/16 = 2:7`
The oxide is `I_(2)O_(7)`.
When dissolved in water it can PRODUCE `HIO_(4)` or `H_(5)IO_(6)`
`I_(2)O_(7) + H_(2)O to 2HIO_(4)`
`I_(2)O_(7) + 5H_(2)O to 2H_(5)IO_(6)`


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