1.

A certain quantity of electricity is passed through an aqueous solution of AgNO_(3) and cupric salt solution connected in series . The amount of Ag deposited is 1.08 g. then the amount of copper deposited is (At. Mass Cu = 63.5 , Ag = 108) .

Answer»

0.6454 G
6.354 g
0.3177 g
3.177 g

Solution :`("Wt. of Cu")/("Wt. of AG") = ("Eq. of MASS of Cu")/("Eq. mass of Ag")`
`("Wt. of Cu")/(1.08) = (63.5//2)/(108)`
or Wt. of Cu = `0.3177` g


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