A certain reactant XO_3^(-) is getting converted to X_2O_7 in solution.the rate constant of this reaction is measured by titrating a volume of the solution with a reducing agent which reacts only with XO_(3)^(-) and X_2O_7.In this process of reduction both the compounds converted to X^(-).At t=0 the volume of the reagent consumed is 30mL and at t=9.212 min.the volume used up is 36 mL.Find the rate constant (in hr^(-1)) of the conversion of XO_3^(-) to X_2O_7 ? Assuming reaction is of I^(st) order (Given that ln 10=2.303, log2=0.30)

A certain reactant XO_3^(-) is getting converted to X_2O_7 in solution

1.	A certain reactant XO_3^(-) is getting converted to X_2O_7 in solution.the rate constant of this reaction is measured by titrating a volume of the solution with a reducing agent which reacts only with XO_(3)^(-) and X_2O_7.In this process of reduction both the compounds converted to X^(-).At t=0 the volume of the reagent consumed is 30mL and at t=9.212 min.the volume used up is 36 mL.Find the rate constant (in hr^(-1)) of the conversion of XO_3^(-) to X_2O_7 ? Assuming reaction is of I^(st) order (Given that ln 10=2.303, log2=0.30)
Answer» Solution :`XO_3^(-) to X_2O_7` a-x ax6=30`implies a=5` `(a-x)xx6+(x/2xx16)=36` `implies x=3` `k=2.303/9.212"LOG"(5/2)=0.1 "min"^(-1) =6 HR^(-1)`