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A certain reaction is nonspontaneous at 298 K. The entropy change during the reaction is 121 J/K . Is the reaction endothermic or exothermic ? What is the minimum value of DeltaH for the reaction ? |
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Answer» Solution :Given that `Delta` +ve for nonspontaneous process. As, `DeltaG=DeltaH-TDeltaS` and `DeltaS=+121J//K` `DeltaH` has to be POSITIVE that is the REACTION is endothermic To calculate the MINIMUM VALUE of `DeltaH`, `DeltaG=0` `:.DeltaH=TDeltaS` or `DeltaH=298xx121J` `DeltaH=36.06kJ` |
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