1.

A certain reaction is nonspontaneous at 298 K. The entropy change during the reaction is 121 J/K . Is the reaction endothermic or exothermic ? What is the minimum value of DeltaH for the reaction ?

Answer»

Solution :Given that `Delta` +ve for nonspontaneous process.
As, `DeltaG=DeltaH-TDeltaS` and `DeltaS=+121J//K`
`DeltaH` has to be POSITIVE that is the REACTION is endothermic
To calculate the MINIMUM VALUE of `DeltaH`, `DeltaG=0`
`:.DeltaH=TDeltaS`
or `DeltaH=298xx121J`
`DeltaH=36.06kJ`


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