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A certain weak acid has a dissociation constant of 1.0 xx 10^(-4). The equilibrium constant for its reaction with a strong base is

Answer»

`1.0 xx 10^(-4)`
`1.0 xx 10^(-10)`
`1.0 xx 10^(10)`
`1.0 xx 10^(14)`

SOLUTION :The equilibrium constant for the NEUTRALIZATION of a weak ACID with a strong base,
`K = (K_(a))/(K_(W)) = (1.0 xx 10^(-4))/(1.0 xx 10^(-14)) = 1.0 xx 10^(10)`


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