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A chain of mass media is attached at two points Aand B of two fixed walls as shown in the figure. The tension between the chain is at A is.... please help me with itno spam!! |
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Answer» As per QUESTIONS the vertical component of tension must BALANCE the weight of the chain. And also it is a case of variable tension since theta is changing. But still MAGNITUDES of horizontal component of tension at each point must be same at every point.Let's tension and point A and point B be T and at midpoint of chain be T'Then 2T SIN theta = mg which gives T = mg/2 cosecAAlso T cos theta= T'so, T' = mg/2 cot theta(NOTE : when you write you should use the symbol of theta instead of writing "theta")HOPE THIS HELPS YOU BETTER PLZ MARK ME AS BRAINLIEST |
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