A chamber is maintained at a uniform magnetic field of 5 × 10^-3 T. An electron with a speed of 5 × 10^7 ms^-1 enters the chamber in a direction normal to the field. Calculate the radius of the path.(a) 15.7 cm(b) 5.7 cm(c) 25.7 cm(d) 75.7 cmThe question was asked by my college professor while I was bunking the class.Question is taken from Motion in Combined Electric and Magnetic Field topic in chapter Moving Charges and Magnetism of Physics – Class 12

A chamber is maintained at a uniform magnetic field of 5 × 10^-3 T. A

1.	A chamber is maintained at a uniform magnetic field of 5 × 10^-3 T. An electron with a speed of 5 × 10^7 ms^-1 enters the chamber in a direction normal to the field. Calculate the radius of the path.(a) 15.7 cm(b) 5.7 cm(c) 25.7 cm(d) 75.7 cmThe question was asked by my college professor while I was bunking the class.Question is taken from Motion in Combined Electric and Magnetic Field topic in chapter Moving Charges and Magnetism of Physics – Class 12
Answer» The CORRECT answer is (b) 5.7 cm The EXPLANATION is: Radius → r = \(\frac {mv}{eB}\) r = \(\frac {(9.1 \, \times \, 10^{-31} \, \times \, 5 \, \times \, 10^7)}{(1.6 \, \times \, 10^{-19} \, \times \, 5 \, \times \, 10^{-3})}\) r = 5.7 cm Therefore, the radius of the path is 5.7 cm.

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